Question

IP A charge of 20.0 μCμC  is held fixed at the origin.

If a -5.00 uC charge with a mass of 4.00 g is released from rest at the position (0.925 m, 1.17 m), what is its speed when it is halfway to the origin? O AZ¢ * * O a? m/s

Answer 1

A)The distance from the origin is, V (0.925-0)*+(1.17-0)) 1= = 0.75 m The kinetic energy of the charge qi is equal to the electric potential energy of the charge q is, (21.0x10^)(5.50x104 0.75 = 26.3 m/s (b)At the x-point x==(0.925) = 0.4625 m At the y-point x==(1.17) = 0.585 m The distance from the origin is, (0.4625-0) +(0.585-02) =0.37 m

The kinetic energy of the charge qı is equal to the electric potential energy of the charge q is, - - MA ") 9-10)20-10 96.01 (20x10°) (5.0*10%) 0.37 =34.9m/s The speed of charge qı when it is halfway to the origin is greater than the speed found in part A Therefore, the correct option is "First one"