1) The lengths of pregnancies in a small rural village are normally distributed with a mean of 263 days and a standard deviation of 15 days. A distribution of values is normal with a mean of 263 and a standard deviation of 15.
What percentage of pregnancies last fewer than 295 days? P(X < 295 days) = %
2) The physical fitness of an athlete is often measured by how
much oxygen the athlete takes in (which is recorded in milliliters
per kilogram, ml/kg). The mean maximum oxygen uptake for elite
athletes has been found to be 68 with a standard deviation of 7.8.
Assume that the distribution is approximately normal.
Find the probability that an elite athlete has a maximum oxygen
uptake of at most 47.7 ml/kg.
Solution :
Given that ,
1) mean = = 263
standard deviation = = 15
P(x < 295) = P[(x - ) / < (295 - 263) / 15]
= P(z < 2.13)
Using z table,
=0.9834
The percentage is = 98.34%
2) mean = = 68
standard deviation = = 7.8
P(x 47.7)
= P[(x - ) / (47.7 - 68) / 7.8 ]
= P(z -2.60)
Using z table,
= 0.0047
1) The lengths of pregnancies in a small rural village are normally distributed with a mean...
The lengths of pregnancies in a small rural village are normally distributed with a mean of 264 days and a standard deviation of 13 days. A distribution of values is normal with a mean of 264 and a standard deviation of 13. What percentage of pregnancies last fewer than 294 days? P(X < 294 days) = % ?
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