1. Find the equation of the curve passing through the point (1, 1) whose differential equation...
Please help (1 point) In this problem we consider an equation in differential form M dx + N dy-0 (- (xy' +y)) dx + (- (x2y + x))dy 0 Find If the problem is exact find a function F(x, y) whose differential, d F(x, y) is the left hand side of the differential equation. That is, level curves F(x, y C, give implicit general solutions to the differential equation. If the equation is not exact, enter NE otherwise find F(x,...
(1 point) In this problem we consider an equation in differential form M dx + N dy = 0. (4x4 + y) dx + (x - y)dy = 0 Find My = Nx = If the problem is exact find a function F(x, y) whose differential, d F(x, y) is the left hand side of the differential equation. That is, level curves F(x, y) = C, give implicit general solutions to the differential equation. If the equation is not exact,...
(1 point) In this problem we consider an equation in differential form M dx + N dy=0. (6x + 6y)dx – (6x + 4y)dy = 0 Find My = N = If the problem is exact find a function F(x,y) whose differential, F(x, y) is the left hand side of the differential equation. That is, level curves F(x, y) = C, give implicit general solutions to the differential equation If the equation is not exact, enter NE otherwise find F(x,y)...
(1 point) Use the "mixed partials" check to see if the following differential equation is exact. If it is exact find a function F(x, y) whose differential, d F(x, y) is the left hand side of the differential equation. That is, level curves F(x, y) = C are solutions to the differential equation (-3e* sin(y) + 4y)dx + (4x – 3e* cos(y))dy = 0 First, if this equation has the form M(x, y)dx + N(x, y)dy = 0: My(x, y)...
Determine whether the given relation is an implicit solution to the given differential equation. Assume that the relationship does define y implicitly as a function of x and use implicit differentiation. -xy -y dy e +y=x+3, dx -wy+X -xy- dy V equivalent to dx Va solution to the differential equation. Therefore, e+ yx+3 y+x Applying implicit differentiation to the equation gives which
(1 point) Use the "mixed partials" check to see if the following differential equation is exact. If it is exact find a function F(x, y) whose differential, dF(, y) gives the differential equation. That is, level curves F(x,y) = C are solutions to the differential equation: dy 4x3 - y dx + 4y2 First rewrite as M(x,y) dic + N(x, y) dy = 0 where M(x,y) = and N(x,y) = If the equation is not exact, enter not exact, otherwise...
dy (c) Write the first order differential equation x-y-x0 in standard form and find its general solution and then find the particular solution passing through (-2,4) (d) r (e) For what values of c does the integadx converge? al-dx converge? x(In x) O Inrlde -1 In x lux 2e Ch) In In xdr dy (c) Write the first order differential equation x-y-x0 in standard form and find its general solution and then find the particular solution passing through (-2,4) (d)...
dy Determine the region in the plane for which the differential equation 1. has a unique V1-y dx solution through the point (Xo. yo) Verify that the function is an explicit solution of the differential equation: 2. x2y" +xy'+y 0; y sin(In x) Give an interval of definition for the solution. Chapter 2 3. The graph represents the graph ofdyf). Sketch a direction field for the differential equation
walk me through this a) Use the formula: k(x) to find the equation of the osculating circle for y In x at the point (1.0) 1+r732 The equation or the circle is: (x+(HS㎡+(y + (2/ b)Show that the osculating circle and the curve (y Inx) have the same first and decond derivative at the point (1.0). Note: findfor the circle using implicit dx differentiation for the circle: dy = 11 and For the curve: y Inx dy dx (1,0) a)...
(1) Find an curve equation for the live tangent to the at the point defined by the giver value of t. Also find value of dry/dx² dy/dx² at this point. a) x = ㅗ y = t t-t t = 2 ttt