SOLUTION;-
GIVEN DATA;-
The switch in the figure is closed at t=0 when the current I is zero.When I = 15 mA,what is the potencial difference across the inductor ?
THE GIVEN ;;
When I = 15 OmA,
the drop across the resistor is V = I x R = 15 x 10^-3 A x 4 x 10^3 Ohms = 60V.
The voltage left is across the inductor and is V = 240 - 60 = 180 V.
The switch in the figure shown is closed at t=0 when the current, i, is zero,...
(3) The RL circuit shown in Figure 3 has a switch that is closed att 0. Assume that the circuit has reached steady state prior to the switch closing. You are given R1 1 kQ, R2-10 kQ, R3-R4-100 k2, L 10 mH, Vs-5 V. (a) [15 pts] Calculate the steady-state inductor current before the switch is closed (b) [16 pts] Give the differential equation as an expression of the inductor current fort>0 (i.e. write the differential equation) (c) 13 pts]...
b) For e circuit shown in Figure 4, the switch S is closed at t = 0. the voltage v (t) across the inductor L, given that v(t) = Vsin2nt ft. R = 100 O [6 points) Calculate the voltage v, (t) ac L = 318.3 mH and f = 50 Hz. Figure 4.
I4(0)
... current through R4 just after switch is closed ... =
0.04196 A
I4(∞) ... current through
R4 after switch has been closed for a very long time ...
= 0.05539 A
IL(∞) ... current through inductor
after switch has been closed for a very long time ... =
0.03767 A
VL,max(closed) ... maximum voltage
across inductor during the time when switch is closed ... =
4.28 V
VL,max(open) ... maximum voltage
across inductor during the time when switch...
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