Question

The following data were recorded in the experiment (E106): mass of calorimeter 60g mass of calorimeter with water 230 g mass of metal specimen 58 g initial temperature of water and calorimeter 20 ᵒC initial temperature of the metal 100 ᵒC Specific Heat Capacity of Calorimeter 0.22 cal/g. Cᵒ Final temperature of the mixture 27 ᵒC What is the heat gained by water in calories?

A. 420

B. 1,610

C.1,190

D. 4,234

Answer 1

Ans . Option "C" =1190 calorie is the correct one....kindly look at the explanation as given below:-

Mass of Calorimeter = 609 Mass of Calo simeter with water = 230g mais of water - Mass of calosimeter) - (mans of Calosmta = (230g-60g) = 170g Initial temperature of water and calo simeter = 20 C specific heat Capacity of Calorimeter = 0.22 callgic Final = 0.92 J/g - C temperature of mixture of water, lalo smetr & metal specific heat Capacity of Water = 4:184J/g °C Water -Water Heat gained by = ' m water AT = 170 g X 4.1845lg CX (27°C-20°c). =(170 X 4,18487) I = 4978,965 = 4978.96 I = 1190 Calorie и: 1 ч.