Question

7.3 Find an equation for the pitching moment with respect to the center of gravity cg and the position of this with respect to Lt to obtain a stable flight. and ,What type of flight condition is it; neutral, stable or unstable? (consider the canard and the wing are symmetrical)

Scanard = 0.2 Swing
medium chord (C¯canard)= 0.45 (C¯wing )

LiftCoefficent CL canard= CL wing

M 66

Answer 1

Con left officient at zero angle of attach w - dee left cunne stope of wing ( Н . cs Lox Cat - Left coffen el taule hern Left www slope of tai dx p egue y teu Cox & Luft of tail at zero angle of attack mo moment coffecent at zero angle of attack &- dcm change of moment coff da wit angle of attack For stability (mo >0 & Cmx Lo This conditions are reg. to make a stable mom

Sol" e Macw. Mact de a li as Assumption +monen D-negnoment Wing conteribution will not remaini scome as the conventional wing-tail configration. Downwash on wing due to concord es negligible Incederne angle of both wing and cancard care zero Wang contribution cosa al sind, 2,1 » C Mcgw = Lw costw (le - Xcg) + Mann megn - Crack T Cew (dt - Xey) wac w

We know cy Cou + Cu Cargo & Crown (Chow to Crane Tu) [de-X) - Low Laage - CrocoT (Crow + Ceas Ku) (do - Xu). . W wa Now tail conteribution M. J L + (xco) M = 48 V S Cat (x3) Dirning by t o suc --Svi se laxa) tsu SwC set Vran

(nt = nS + C+ (Xcg) Sw Sunce St=0.2 Sw Cat = no.2 CL+ XXcg - 2

Cat Chor & Carta So eg" @ becomes Cm- no.2 (C4 + Cesta c) (Xcg) - no.2 Clot Xcg + no. 2 Car & Xez DV しxt Ć Comparing with standard equ wa (no + Cex. С.. по 2 С. Х. Cea = no.2 Clas X cg

Total tail due contribution and wong to Con Cracot no.2 Leon Tag G Low لعام سا noz cows Xog). Consider can and a wong core symmetrical arfoil & win = Crow ennen so loto & Crowd Cor: Crown - [. ( -no_240x9] Abe CW - С. А. , = Cre) no.ch

menace w - Cest - Xe-no.2 X c.ph Considu nal me Cnaicu - C dt - 1. 2X nalw C Sin Cina.cw >o = mo > so the stable configration is statically as any es already regature Ldw and (no is already possitive