Question

50 mph A long semi-circular hut with a 2.44 m (8 ft) radius is exposed to extreme windy conditions in a desert. The wind blows uniformly at a speed of 22.4 m/s (50 mph) as shown in the figure. The upstream pressure is atmospheric (gage pressure = 0). Determine the resultant drag and lift forces exerted on the hut due to the wind Assume the pressure inside the hut is also at atmospheric pressure Problem Description Questions What are the drag and lift forces acting on the hut for the stated conditions? Consider both inside and outside pressure. Approach • Base the analysis on potential flow past a fixed cylinder Take the density of air as 123 Kg/m Important Information 1. Solve the above problem on aerodynamic forces on a blunt body

Answer 1

Foon data U = 22,4 m See 8=2.44 m C Now For potential Flow post cylinder Pessuae outside but Poutside - Ps = Pote 34² (1-4 sive) - lift Food & docg com be calculated b y Integrating Pressure over cylinder Now total daug Fx = -√ [ Pout - Pin Iocoro do - - 5 [rot'svěci usin? 03 –P.]rcovo do - Bu ſcoso do +298W Ś sido caso de -[- su sine + % su'suto]. - [o-) = 0 Ex = dong = 0

lift tone ñ Fy = - § 1 Post - Pin] sin ordo -- [ Po týpu(1-escindo) –pe] ring do .-250? ['be's swe do -2 5-in odo] 10 d (0) 1 se ) 2 [Coco 10303-) 3 - 03038,-) ense ([ C**-) 6-9-]-[66-1) 6-37).])ense-- (3-),nse. OV S4034 = Sxx 2.44*1.25 X (22.92 Fy = 2509.8 Nm klift