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imagine that in a certain region of an equipotential diagram, the equipotentials are spaced 2 mm...

imagine that in a certain region of an equipotential diagram, the equipotentials are spaced 2 mm apart, and the potential increases by 0.1V per equipotential curve as one moves towards the left. What is the magnitude and direction of the electric field at that point

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Answer #1

E= -dV/dx = - 0.1/0.002 =   -50 N/C directed to the right

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