Question

What would be the speed of the boxes in problem 5 if the kinetic friction coefficient between box A and the surface it slides on were 0.20? Solve using conservation of energy 6.

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Answer #1

now in this part we take intial velocity, U= 1.565 m/susing

conservation of energy

frictional energy loss= change in kinetic energy of system

-u(mg) d= 0.5m(v^2-U^2)

-0.2*12*9.8*0.5= 0.5*12*(V^2-1.565^2)

v= 0.699 m/s

comment in case any doubt..goodluck

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