Question

10. You shoot a 250g arrow straight up with an initial velocity of 12 m/s, ignoring air resistance: a. How high does it go? b. How long does it take to hit the ground?

Answer 1

* 10)sol: DATA (m=(2500) (a)= (2m/sec) (a)(41) max= (b)([p] = ? - soli

(a) Hese given problem is an example of vertical projection of body s in this projection, maximum height reached by a body from ground level is known by the formulario . whese (619= (initial velocity) 1 (g)- Facceleration] due to ное, . [ gravity (93=(7.8 ms) [:constant ] (6A) = (izm/sec) (chiumax) = ? lors max] =)

.: (=) SH)wav) = .-7-----Forax) TITITITII (TTTIIIII 6.35m) -H) max]=47.35m) is height (9)=(1.8 m/s2) reached by adow.

(6) In vertical projection, time taken by an object to reach ground level after its projection is known as "time of flight (T.f)," It is given by the formulae :- r where ( 1 (W)= (initial velocity) (O)=facceleration 7 Hде (u) = (12 m/sec) due to (9) = 69.8 ms2) L gravity (TF)=9

12.45 sec) (Te) =(2.45 sec) I is time taken I by arrow to hit the ground

*conclusion: - *a) [CH Jmay] = 67.35m) * (b) (TP)=6.45 sec)