Question

Problem 2. Leveling observations are shown below. Using any acceptable format, write the field notes. Write the adjusted elevations and the page check for the entire level line/loop. Show your computations as necessary and sufficient although they are not part of the field notes. True Elevations: BM COM = BM ANT = 505.22 ft 497.74 ft Foresight (ft) Station BM COM TP 1 TP 2 BM BAT TP 3 TP 4 TP 5 BM ANT Backsight (ft) 6.44 5.67 4.19 3.03 2.75 2.66 4.11 6.89 4.44 5.89 5.07 4.77 3.88 5.46

Answer 1

To solve this question we can use two basic method.

1. Height of instrument method-- in this method height of instrument is calculated at every change point of theodolite.

2. Rise and fall method--- in this method we calculate the elevation of next point in the form of rise or fall with respect to just previous point.

Let's us adopt height of instrument method whose calculation is given as below.

Calculation..

Generaly these data are represented in field book which is as.

field nate to represent the We adept elevation the following data ... Station fight Back @BS) Intermediate fight Intermediate fight (HS) fore sight fore (FS) elevation / adjust Telovation Given data to fined the elevation of peg level, we use height of instrument method, In this method, height of instrument (HI) i I = tom) + Buck sight Den elevation of mert ) = HI - fore-sight I position of (Srestaumont 1 l station is not change) -- Calculation : te as given in question, elevation of BM.com=505.22 ft. g Thon when instrument is at Bm com HI= 505-22 +6.44 = 51166 elevation of TP1 = 511.66-6.89 = sou.77 ft Now instrument is skifted to TP1 HI = 504077 +5.67 = 510.04 elevation of TP 2 = 510044-4.44= 506.00 ft

flow instrument is again in this way we calculate as follow in field Note . shifted, int all the reading and represend them Calculated. Elevation. IS H.J. 1 Remark (True) adjusted - elevation (given 505.22 511.66 Station BS IBM Com Gouu TP1 5.67 TP2 4019 505.22 6.89 510.44 504.77 4.44 510:19 506.00 BMBAT 3.03 5.89 507.33 Sou.3 TP3 2.75 5.07 505.01 502.26 TP4 2.66 500:24 499.02 TPS 4.11 3.88 503.13 BM ANT 5.46 497.67 1197.74 Incomect Sum > E=28.85 E=364 Check of data a EBS – Efs = Last Reduced lend- first Rili - 28.85-36:4 = 497.67 - 505.22 -7.55 = -7.55 It means data collected és comect. I but here actual or tove elevation of BM ANT i u7.74 I which ů not equal to ugr.67 (calculated R.L.) which means I there is error in readings. (equal at all stations

As this error can not be directly distributed among the any reading, so we have to either recollect/or reperform the experiment (whole) on adjust the elevation as addre conected done in last reduced lend.. but which given incomect result so that is not suitable.