Question

Qui A Means - CI and hypothesis testing NAME The average undergraduate cost of tuition, fees and books for a two year college is $10.560 Four years later, a random sample 36 two year colleges, had an average cost of tuition fees and books of $11,380 and a standard deviation of $1300, with a normal distribution. Ata - 2%, has the average cost of two-year college increased? 1) Check and state the conditions for statistical inference 5) Calculate the standard error and sketch the model, marking the center and SD's 6) Calculate the p-value, showing ALL the work. 7) State the conclusion, remember there are three parts. Remember that a=2% or a.02.
really need some help here, antthing works. my teacher isnt putting abythingn on canvas so its up to us to do the hw

Answer 1

(1) Null and Alternative Hypotheses The following null and alternative hypotheses need to be tested: Ho: u = 10560 Ha: p > 10560 This corresponds to a right-tailed test, for which a t-test for one mean, with unknown population standard deviation will be used. (2) Rejection Region Based on the information provided, the significance level is a = 0.02, and the critical value for a right-tailed test is te = 2.133. The rejection region for this right-tailed test is R=t:t> 2.133 (3) Test Statistics The t-statistic is computed as follows: t=- X - NO s/n 11380 – 10560 1300/736 -= 3.785 (4) Decision about the null hypothesis Since it is observed that t = 3.785 > te = 2.133, it is then concluded that the null hypothesis is rejected. Using the P-value approach: The p-value is p= 0.0003, and since p= 0.0003< 0.02, it is concluded that the null hypothesis is rejected. (5) Conclusion It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that the population mean u is greater than 10560, at the 0.02 significance level. Confidence Interval The 98% confidence interval is 10851.827 < \ < 11908.173. Graphically. T-Test Results: t-stats = 3.785, p-value =0.0003 0.40 0.35 0.30 0.25 0.20 0.15 0.10 0.05 0.00 -4.0 -3.5 -3.0 -2.5 -2.0 -1.5 -1.0 -0.5 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0

o = 1300 n = 36 we then find that that the standard error se in this case is equal to: 1300 se = se = c = 20 = 216.667 V36 which concludes the calculation.
1) Conditions -

Sample should be from normal population.

Selection of sample should be random.

2) Test Statistics = 3.785

3) P value = 0.0003

4) Decision - Reject H0 if p value < 0.02

5) Conclusion - Average cost of two years of college increased. PL??