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For this cerise, you can simte the described conditions by changing the values in the Run Experiment tool under the Experimen

sorry the final temp is 30.19 C
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Answer #1

Mmol of NaOH = 78×1.7 => 132.6 mmol

mmol of HNO3 =1.9×94 => 178.6 mmol

Q = ms∆T

= 172×4.184×10.19

= 7333.21 J

∆H = -7333.21/0.1326

= -55.3 kJ/mol

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