We know that the Earth moves about the Sun due to the gravity force exerted by...
We know that the Earth moves about the Sun due to the gravity force exerted by the Sun, that is, the Earth is a “satellite” to the Sun, just like the moon to the Earth. Assume the Earth follows uniform circle motion about the Sun, and ignore gravity force due to objects other than the Sun. Estimate the orbital speed of the Earth = _______ m/s?
The Earth has mass =5.98 x 1024 kg and radius 6.4
x 106 m.
The Sun has mass 1.99 x 1030 kg and radius 7 x
108 m.
The center-to-center distance between the Sun and the Earth is 1.5
x 1011 m.
Homework Answers
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We know that the Earth moves about the Sun due to the gravity
force exerted by...
Mass of the Sun is 1.99 × × 1030 kg, mass of the Earth is 5.98...
Mass of the Sun is 1.99 × × 1030 kg, mass of the Earth is 5.98 × × 1024 kg, mass of the Moon is 7.35 × × 1022 kg. Orbit radius of the Earth is 1.50 × × 1011 m, orbit radius of the Moon is 3.84 × × 108 m. 1) Determine the magnitude of the net force of gravity acting on the Moon during an eclipse when it is directly between Earth and the Sun. (Express your...
Mass of the Sun is 1.99 × 1030 kg, mass of the Earth is 5.98 ×...
Mass of the Sun is 1.99 × 1030 kg, mass of the Earth is 5.98 × 1024 kg. Orbit radius of the Earth is 1.50 × 1011 m. 1) Determine the magnitude of the force of gravity between the Sun and Earth. (Express your answer to three significant figures.)
Please include enough steps in your solution. During a lunar eclipse, the Moon, Earth, and Sun...
Please include enough steps in your
solution.
During a lunar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Earth between the Moon and the Sun. The Moon has a mass of 7.36 1022 kg; the Earth has a mass of 5.98 x 1024 kg; and the Sun has a mass of 1.99 x1030 kg. The separation between the Moon and the Earth is given by 3.84 x 108 m; the separation between the Earth...
e alignment of the sun, earth, and orce FSM that the sun exerts on the moon...
e alignment of the sun, earth, and orce FSM that the sun exerts on the moon is per- 5.98 × 1024 kg, 8. The distances shown in the drawing are rawing (not to scale) shows on pendicular to the force FeM that the earth exerts on the m are: mass of sun = 1.99 × 1030 kg, mass of earth = mass of moon = 7.35 × 1022 k SM-1.30 × 10 11 m and rEM-3.85 × 108 m. Determine...
During a solar eclipse the Moon is positioned directly between Earth and the Sun. Find the...
During a solar eclipse the Moon is positioned directly between Earth and the Sun. Find the magnitude of the net gravitational force acting on the Moon then, due to both Earth and the Sun. The masses of the Sun, Earth, and the Moon are 1.99 x100 kg, 5.98 x1024 kg, and 7.36 x 1022 kg, respectively. The Moon's mean distance from Earth is 3.84 × 108 m, and Earth's mean distance from the Sun is 1.50 x 1011 m. The...
Using the formula for gravity, find the force of gravity on a 1.2-kg mass at Earth's...
Using the formula for gravity, find the force of gravity on a 1.2-kg mass at Earth's surface. (The mass of Earth is 6 x 10M kg, and its radius is 6.4 x 106 m.). Express your answer to two significant figures and include the appropriate units. く1024 kg) and the Moon mass-74x 1022 kg Find the force of gravity between Earth (mass-6.0 is 3.8 x 108 m. The average Earth Moon distance Express your answer to two significant figures and...
A satellite is in a circular orbit around the Earth at an altitude of 2.52 106...
A satellite is in a circular orbit around the Earth at an altitude of 2.52 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law: T2 =(4π^2/GMs)r^3 so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 106 m, and the mass of the Earth is 5.98 1024 kg.) _______________h (b) Find the speed of the satellite. _________km/s (c) Find the acceleration of the satellite....
7) Given the mass of the sun (m,-1.99 x 1030 kg ) and the mass of...
7) Given the mass of the sun (m,-1.99 x 1030 kg ) and the mass of the earth (me-5.98 x 1024 kg) and the distance between them (150 billion meters), find the amount of charge required on both the sun and earth to exactly balance the attractive gravitational force.
Acceleration due to gravity on board of your spaceship that orbits Jupiter is 25.89 m/s. How...
Acceleration due to gravity on board of your spaceship that orbits Jupiter is 25.89 m/s. How high is your spaceship above Jupiter's cloud tops? Express your answer in kilometers and round it to the nearest integer. M Jupiter = 1.90 x 104 kg; R Jupiter = 69,911 km. Your cosmic journey brought you into the vicinity of a neutron star. In fact, you are orbiting this neutron star at an orbital distance of 22.424 kilometers. The neutron star has mass...
FERENCES MAILINGS REVIEWVIEWFoxit PDF The force of gravity, F, exerted between two objects is equal to...
FERENCES MAILINGS REVIEWVIEWFoxit PDF The force of gravity, F, exerted between two objects is equal to the product of the gravitational constant, G, the mass of the irst object, m, and the mass of the second object, ma, divided by the square of the distance between their centers, d. This is often used to determine the gravitational attraction behween two massive bodies, such as planets, in space. a. Write the formula for F described in the situation above. Type your...
Please include enough steps in your
solution.
During a lunar eclipse, the Moon, Earth, and Sun all lie on the same line, with the Earth between the Moon and the Sun. The Moon has a mass of 7.36 1022 kg; the Earth has a mass of 5.98 x 1024 kg; and the Sun has a mass of 1.99 x1030 kg. The separation between the Moon and the Earth is given by 3.84 x 108 m; the separation between the Earth...
e alignment of the sun, earth, and orce FSM that the sun exerts on the moon is per- 5.98 × 1024 kg, 8. The distances shown in the drawing are rawing (not to scale) shows on pendicular to the force FeM that the earth exerts on the m are: mass of sun = 1.99 × 1030 kg, mass of earth = mass of moon = 7.35 × 1022 k SM-1.30 × 10 11 m and rEM-3.85 × 108 m. Determine...
During a solar eclipse the Moon is positioned directly between Earth and the Sun. Find the magnitude of the net gravitational force acting on the Moon then, due to both Earth and the Sun. The masses of the Sun, Earth, and the Moon are 1.99 x100 kg, 5.98 x1024 kg, and 7.36 x 1022 kg, respectively. The Moon's mean distance from Earth is 3.84 × 108 m, and Earth's mean distance from the Sun is 1.50 x 1011 m. The...
Using the formula for gravity, find the force of gravity on a 1.2-kg mass at Earth's surface. (The mass of Earth is 6 x 10M kg, and its radius is 6.4 x 106 m.). Express your answer to two significant figures and include the appropriate units. く1024 kg) and the Moon mass-74x 1022 kg Find the force of gravity between Earth (mass-6.0 is 3.8 x 108 m. The average Earth Moon distance Express your answer to two significant figures and...
7) Given the mass of the sun (m,-1.99 x 1030 kg ) and the mass of the earth (me-5.98 x 1024 kg) and the distance between them (150 billion meters), find the amount of charge required on both the sun and earth to exactly balance the attractive gravitational force.
Acceleration due to gravity on board of your spaceship that orbits Jupiter is 25.89 m/s. How high is your spaceship above Jupiter's cloud tops? Express your answer in kilometers and round it to the nearest integer. M Jupiter = 1.90 x 104 kg; R Jupiter = 69,911 km. Your cosmic journey brought you into the vicinity of a neutron star. In fact, you are orbiting this neutron star at an orbital distance of 22.424 kilometers. The neutron star has mass...
FERENCES MAILINGS REVIEWVIEWFoxit PDF The force of gravity, F, exerted between two objects is equal to the product of the gravitational constant, G, the mass of the irst object, m, and the mass of the second object, ma, divided by the square of the distance between their centers, d. This is often used to determine the gravitational attraction behween two massive bodies, such as planets, in space. a. Write the formula for F described in the situation above. Type your...
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