21.0 g NaHCO_3 in 480.0 mL solution 57.0 g H_2SO_4 in 220.0 mL solution M =

Question

Question

Answer 1

Answer #1

molarity = weight of substance * 1000/gram molar mass * volume of solution in ml

= 21*1000/84*480 = 0.52M

molarity = weight of substance * 1000/gram molar mass * volume of solution in ml

= 57*1000/98*220 = 2.64 M

Answer 2

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