Let
L = 2 cm = 0.02m
a = 1 cm = 0.01 m
b = 1 + 2 = 3 cm = 0.03 m
When I is the current through the wire,
magnetic flux through the loop = (mue*I*L/(2*pi))*ln(b/a)
induced emf in the loop = change in megnetic flux/time
= (mue*L/(2*pi))*ln(b/a)*(dI/dt)
= (4*pi*10^-7*0.02/(2*pi))*ln(0.03/0.01)*100
= 4.39*10^-7 volts
induced current in thr loop, I = induced emf/R
= 4.39*10^-7/0.01
= 4.39*10^-5 A
A 20 cm times 20 cm square loop of wire lies in the xy-plane with its...
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