Question

Course Home <HW14 CHBP1 Problem 8.10 Constants Part A On a frictionless air track, a 0.130 kg glider moving at 1.35 m/s to the right collides with and sticks to a stationary 0 255 kg glider What is the net momentum of this two-glider system before the collision? nνα ΑΣφ kg m/s p Request Answer Submit Part B What must be the net momentum of this system after the collision?

Answer 1

Part A

The momentum of the system = momentum of moving glider + momentum of stationary glider

= 0.130*1.35 + 0.255*0

=0.1755 Kg. ms-1

Part B

It should be 0.1755 Kg.ms-1

Part C

Because of law of momentum conservation

Part D

After collision

total mass of the system=0.130+0.255

=0.385

As momentum is conserved

Momentum after collision=0.1755

Speed of gliders=0.1755/0.385

=0.456 ms-1

PSS 8.1

Part C

PFi,x = MF*(Vx) = 0

PFi,Y = MF*(Vy) = MF*(VFi)

MF=Mass of Falcon

Note Vx is zero as the velocity is vertical hence horizontal component is 0.

PRi,x = MR*(VRi)

PRi,Y = MR*(Vy) = 0

MR=Mass of Raven

Note Vy is zero as the velocity is horizontal hence vertical component is 0.