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NOTE: Show all steps in your solutions. Only partial credit will be given if steps are not shown though the final answer is c

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lo z = xtiy 6(2) cot z = cos z Sinz - 2x Coo (ariy) Sin (ax-iy) 2 Sin (atiy) Sin (X-iy) X 2 cos (atvy) sin(x-iy) 2 Sin( altiy5 6(2): Sin2x cosh he he Cosaa sinh coshy - Cosza => 6(2) - sinza sinh zy ? + (032x-loshzy cos2a-coshzy ro = (279 u ^? + a u

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