Question

Objectives:

Use strings and string library functions.

Write a program that asks the user to enter a string and output the string in all uppercase letters. The program should then display the number of white space characters in the string. You program should run continuously until the user enters an empty string. The program must use the following two functions:

A function called count_spaces that counts the number of white spaces inside a string. int count_space(char str[]);

which tell you how many spaces are in the string. The ‘\0’ is still at the end of the string, so the loop control will be same.

1. A function called to_uppercase that converts all the characters in a string to uppercase letters.

     void to_uppercase(char str[]);

Now your program will run something like this:

Enter a string:
A C string is terminated by a null character.

String Entered:
A C STRING IS TERMINATED BY A NULL CHARACTER.
The string has 8 white spaces.

Since we are passing the actual array to the function and not making a copy, any changes that we make to the array happen directly in the original array that was passed in.

Hints:

• Make sure to include <string.h>

• Use the function fgets to read a string into an array of characters.

• Remove the end-of-line character ('\n') from the string by replacing it with the null

  character ('\0')

• If the user hits the enter key without typing anything, then after removing the '\n',

  the string will be empty.

• Use the function strlen to test if the string is empty.

          if (strlen(line) == 0)
  

Answer 1

Program: #include<stdio.h> #include<string > int count space (char str[]) int lengthstrlen (str) int count = 0 foc (1 = 0; i<length; 1++) if (stnli] ') count++ return count void to uppercase(char strlI) int c = 0; while (str[c] != '\0') Stt int main() char strl100]; int w=0, i; printfl"nEnter a String:"); fgets(str, 100, stdin); if (strlen (stc)0) printf( "Enter the string whose length greater than "); printf("String Entered: \n"); int val - count space (str); printfl la str) printf("\nThe, string has %d white spaces\n", val) ; system("pause"); return 0;

Sample output: clusers 203470 documentsivisual studio 20151Projects Project1351Debug Project135.exe Enter a String:A C string is terminated by a null character String Entered: A C STRING IS TERMINATED BY The string has 8 white spaces A NULL CHARACTER Press any key to continue . . -
Editable code:

#include<stdio.h>
#include<string.h>

int count_space(char str[])
{
   int length = strlen(str);
   int i, count = 0;
   for (i = 0; i<length; i++)
       if (str[i] == ' ')
           count++;
   return count;
}

void to_uppercase(char str[])
{
int c = 0;

while (str[c] != '\0')
{
if (str[c] >= 'a' && str[c] <= 'z')
{
str[c] = str[c] - 32;
}
c++;
}
}
int main()
{
   char str[100];
   int W = 0, i;
   printf("\nEnter a String:");
   fgets(str, 100, stdin);
   if (strlen(str) == 0)
   {
       printf("Enter the string whose length greater than 0");
   }

   printf("String Entered: \n");
   int val = count_space(str);
   to_uppercase(str);
   printf("\n%s", str);
   printf("\nThe string has %d white spaces\n", val);
  
   system("pause");
   return 0;
}