Solution:
Part a
We are given p=0.20, n=17
P(X≥x) = 0.48
P(X<x) = 1 – 0.48 = 0.52
So, by using Binomial table,
X = 3 approximately
Part b
We are given p = 1 – 0.20 = 0.80, n = 17
P(Y≥y) = 0.78
P(Y<y) = 1 – 0.78 = 0.22
So, by using binomial table,
Y = 12 approximately
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