You are watching a stunt-woman set up to be shot from a cannon and (hopefully) over...
You are watching a stunt-woman set up to be shot from a cannon and (hopefully) over a wall. The cannon will launch her at an angle of 60 ̊above horizontal and a speed of 10 m/s.
As the stunt-woman flies, the horizontal component of her velocity will remain constant, and only the vertical component of her velocity will change.
What is the maximum height wall the stunt-woman can be launched get over with this cannon?
Homework Answers
In y direction
VF=0
Vi=10sin60=8.66 m/s
By vf^2=vi^2+2gHmax
Hmax=8.66^2/2*9.8
Hmax=3.826m
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