Question

Question 30 3 pts How would the reaction respond if some PtO is removed from the reaction mixture at equilibrium? CS2(g) + 2H
0 0
Add a comment Improve this question Transcribed image text
Answer #1

2 KE 2 a CS2 anzo apk → K= [H25] 2 Question 26 The given equilibrium in C5218)+2420(8) +P+(s) = C(s) + 2H25(%) + PŁO(s) Shrantemperature increased, or the final concentration of co, altamed by deereasing from any given en concentration of co, beforel

Add a comment
Know the answer?
Add Answer to:
Question 30 3 pts How would the reaction respond if some PtO is removed from the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Le Chateler's principle In the chart below: • Indicate the color of each solution as darker...

    Le Chateler's principle In the chart below: • Indicate the color of each solution as darker or lighter than the control after the addition of the specified substance. • Indicate the direction the equilibrium shifted as "toward products" or "toward reactants" based on the color change. • Based on the direction of the shift, indicate the substance(s) that increased which will either be the two reactants present on the reactant side of the equilibrium equation or the complex present on...

  • Name: 1. An exothermic reaction is allowed to reach equilibrium. If the temperature of the reaction...

    Name: 1. An exothermic reaction is allowed to reach equilibrium. If the temperature of the reaction mixture is decreased, the equilibrium will shift towards the product side: True False [1pt] 2. For the reaction C(s) + H2O(g) CO(g) + H2(g) a decrease in concentration of C(s) will cause the reaction to shift to the left oTrue False [1pt] 3. Define the following terms: [1.5pts] a. Activation Energy b. Exothermic Reaction c. Equilibrium [1p) 4. Determine the equilibrium constant K C(s)...

  • 14) In an exothermic reaction, heat can be considered a A) reactant B) product C) rate...

    14) In an exothermic reaction, heat can be considered a A) reactant B) product C) rate D) catalyst E) determinant 15) Any reaction that absorbs 150 kcal of energy can be classified as A) endothermic B) exothermic C) activated D) reduction E) oxidation 16) The is the energy difference between reactants and products in a chemical reaction. A) transition energy B) activation energy C) product energy D) overall energy E) heat of reaction 17) For the reaction of carbon with...

  • Q(18) NI(CO)49) - Ni(s) + 4 CO(g)Adding nickel (solid) to this reaction will cause the equilibrium...

    Q(18) NI(CO)49) - Ni(s) + 4 CO(g)Adding nickel (solid) to this reaction will cause the equilibrium to A) Shift toward the products B) Shift toward the reactants C) remain unchanged D) increase the temperature E) it depends on the amount added Q(19) CO2 + H2 -CO + H2O Adding a catalyst to this reaction will cause the COD at equilibrium to A) Shift toward the products B) Shift toward the reactants C) remain unchanged D) increase the temperature E) it...

  • 14. A catalyst a. Participates in the reaction and b. Dec c. Increases the activation e...

    14. A catalyst a. Participates in the reaction and b. Dec c. Increases the activation e d. Binds to the reactants and releases them sequentially the reaction and changes the product release reases the activation energy required for the reaction 15. In an exothermic reaction, if heat is removed from the reaction a. Equilibrium shifts to the right b. Product formation increases c. Increase the value of K d. All the above 16. Initially, a mixture of 0.100 M No,...

  • Question 1 In the reaction: CO2(g) + C(s) --> 2CO(g), how might the concentration of C(s)...

    Question 1 In the reaction: CO2(g) + C(s) --> 2CO(g), how might the concentration of C(s) (graphite) affect the equilibrium concentration of the product CO(g)? a. It does not affect it at all because C(s) is not included in the expression of the equilibrium constant. Thus, whether C(s) is present or not does not affect the reaction. b. It doesn't affect it as long as there is C(s) present during the reaction (i.e. C(s) is in excess so it does...

  • 5 pts Question 3 The reaction and equilibrium constant are provided. 2 SO2 (9) + O2...

    5 pts Question 3 The reaction and equilibrium constant are provided. 2 SO2 (9) + O2 (g) 92 SO3 (g) Kc = 5.8 x 103 Which direction will the reaction proceed if [SO2] = 0.15 M, [O2] = 0.10 M and (SO3) = 0.50 M? shifts to make more reactant shifts to make more product no shift

  • Homework #7A Name: Due date: 3-16-20 1. How many moles of water, H20, contain 9.03 *...

    Homework #7A Name: Due date: 3-16-20 1. How many moles of water, H20, contain 9.03 * 10molecules of water? 2. How many molecules are present in 4.9 moles of L,CO3. 3. How many moles of oxygen are present in 4.9 moles of L.COM 4. How many Li atoms are in 4.5 moles of Li? 5. Calculate the mass, in grams, for 3.75 10 molecules of C2Hs. 6. Calculate the mass, in grams, for 3.5 moles of CHO. 7. Calculate the...

  • = 1-Lab from Chapter 15 Eq and Le Chat - Word Search Design Layout References Mailings...

    = 1-Lab from Chapter 15 Eq and Le Chat - Word Search Design Layout References Mailings Review View Help Add i nk Ink to Ink to Drawing Ink Pen Editor Shape Math C anvas Replay Convert Replay Open the Le Chatlier's Principle Activity found in your textbook, Interactive General Chemistry. (Section 15.6, Figure 15.9), run the simulation and complete the following questions. Pens insert 1. Start with the default settings where K - 1.00. a. Write the expression based on...

  • To understand how elementary steps make up a mechanism and how the rate law for an...

    To understand how elementary steps make up a mechanism and how the rate law for an elementary step can be determined. Very often, a reaction does not tell us the whole story. For instance, the reaction NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) does not involve a collision between an NO2NO2 molecule and a COCO molecule. Based on experimental data at moderate temperatures, this reaction is thought to occur in the following two steps: NO2(g)+NO2(g)→NO3(g)+NO(g)NO2(g)+NO2(g)→NO3(g)+NO(g) NO3(g)+CO(g)→CO2(g)+NO2(g)NO3(g)+CO(g)→CO2(g)+NO2(g) Each individual step is called an elementary step. Together, these...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT