Factor A has 3 treatments and factor B has 4 treatments, 10 replicated for each unique treatment combination. Complete the 2-way ANOVA
Homework Answers
Add Answer to:
Factor A has 3 treatments and factor B has 4 treatments, 10
replicated for each unique...
The following results are from an independent-measures, two-factor study with n = 5 participants in each...
The following results are from an independent-measures, two-factor study with n = 5 participants in each treatment condition Factor A: Factor B: 3 M=5 M=8 M=14 T=25 T=40 T=70 SS 30 SS 38 SS46 n=5 n=5 n=5 2 T= 15 T-20 T=40 SS 22 SS 26 SS 30 ZX2 = 2,062 Use a two-factor ANOVA with α = .05 to evaluate the main effects and interaction. Source df MS Between treatments A x B Within treatments Total F Distribution Numerator...
A study of 6 different weight loss programs involved 120 subjects. Each of the 6 programs...
A study of 6 different weight loss programs involved 120 subjects. Each of the 6 programs had 20 subjects in it. The subjects were followed for 12 months. Weight change for each subject was recorded. We want to test the claim that the mean weight loss is the same for the 6 programs. (a) Complete the following ANOVA table with sum of squares, degrees of freedom, and mean square (Show all work): Source of Variation Sum of Squares (SS) Degrees...
The following results are from an independent-measures, two-factor study with n condition. 10 participants in each...
The following results are from an independent-measures, two-factor study with n condition. 10 participants in each treatment Factor B Factor A 2 T 40 M=4.00 SS = 50 T=50 M = 5.00 SS = 60 T= 10 M 1.00 SS 30 T=20 M 2.00 SS 40 N = 40; G = 120; Σ? = 640 Use a two-factor ANOVA with α =。05 to evaluate the main effects and the interaction Source df MS Between treatments AxB Within treatments Total For...
In a completely randomized design, ten subjects were assigned to each of three treatments of a...
In a completely randomized design, ten subjects were assigned to each of three treatments of a factor. The partially completed ANOVA table is shown below. Complete parts a through d. Source DF Sum of Squares Mean Square F-Ratio P-Value Treatment (Between) 831.84 Error (Within) Total 1103.41 ?a) What are the degrees of freedom for? treatment, error, and? total? The degrees of freedom for treatment are nothing. ?(Simplify your? answer.) The degrees of freedom for error are nothing. ?(Simplify your? answer.)...
please show work for each! ΑΙ Factor B B. B2 T = 40 T = 10...
please show work for each!
ΑΙ Factor B B. B2 T = 40 T = 10 M=4 M= 1 SS-50 SS = 30 Factor A A2 T-50 M=5 SS - 60 T = 20 M = 2 SS = 40 N-40 G = 120 EX =640 Use a two-way ANOVA with a=0.05 to evaluate the main effects and the interaction. m Source SS df MS F Between treatments | 1 6.67 I 2.00 Factor A (ROWS) 18.00 Factor B (COLUMNS)...
Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatm...
Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatment, Error, and Total Which of the following reasons best explains why the within-treatments sum of squares is sometimes referred to as the "error sum of squares"? O Differences among members of the sample who received the same treatment occur when the researcher O Differences among members of...
Question Completion Status QUESTION 4 Anova: Single Factor SUMMARY Groups Count Sum Average Variance A 4...
Question Completion Status QUESTION 4 Anova: Single Factor SUMMARY Groups Count Sum Average Variance A 4 108 27 32.66666667 B 4 96 24 13.33333333 4 120 30 56 ANOVA Source of Variation SS df F crit MS P-value F Treatments 72 36 1.058823529 0.386396621 4.256494729 Error 306 9 34 Total 378 11 Based on the Results above of Single Factor ANOVA: the MSTR O 36 O 378 O 72 O 34 Click Save and Submit to save and submit. Chick...
An experiment has a sinale factor with 3 aroups and 5 values in each aroup. In...
An experiment has a sinale factor with 3 aroups and 5 values in each aroup. In determining the among-group variation, there are 2 degrees of freedom. In determining the within-group variation, there are12 degrees of freedom In determining the total variation, there are14degrees of freedom. Also, note that SSA = 42 SsW 84, SST= 126, MSA = 21, MSW = 7, and FSTAT = 3. Complete parts (a) through (d). a. Construct the ANOVA summary table and fill in all...
The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three repl...
The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted the following data: SST 291, SSA 26, SSB 25, SSAB 180. =.05, Show entries to 2 decimals, If necessary Set up the ANOVA table and test for significance using the answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value X X Factor A Factor B Interaction 24 Error 35 Total...
Problem 4: Complete the ANOVA table based on the following data: Replications Standard Deviation ...
Problem 4: Complete the ANOVA table based on the following data: Replications Standard Deviation Factor A Level 1 Level 2 Mean 15 ANOVA Table Degree Freedom of Sum of square Mean sum of F-valuc Source error square error Treatment Error Total NA NA NA Recall that for single-factor ANOVA, we have the following -SSTreatments+SSp where ss,-Σ Σ(y)-T)-total sum of squares n Σ(vi-r-treatment sum of squares i- SSE _ Σ Σ(w-5)2-error sum of squares Given a dataset like the following: Treatment...
The following results are from an independent-measures, two-factor study with n = 5 participants in each treatment condition Factor A: Factor B: 3 M=5 M=8 M=14 T=25 T=40 T=70 SS 30 SS 38 SS46 n=5 n=5 n=5 2 T= 15 T-20 T=40 SS 22 SS 26 SS 30 ZX2 = 2,062 Use a two-factor ANOVA with α = .05 to evaluate the main effects and interaction. Source df MS Between treatments A x B Within treatments Total F Distribution Numerator...
The following results are from an independent-measures, two-factor study with n condition. 10 participants in each treatment Factor B Factor A 2 T 40 M=4.00 SS = 50 T=50 M = 5.00 SS = 60 T= 10 M 1.00 SS 30 T=20 M 2.00 SS 40 N = 40; G = 120; Σ? = 640 Use a two-factor ANOVA with α =。05 to evaluate the main effects and the interaction Source df MS Between treatments AxB Within treatments Total For...
please show work for each!
ΑΙ Factor B B. B2 T = 40 T = 10 M=4 M= 1 SS-50 SS = 30 Factor A A2 T-50 M=5 SS - 60 T = 20 M = 2 SS = 40 N-40 G = 120 EX =640 Use a two-way ANOVA with a=0.05 to evaluate the main effects and the interaction. m Source SS df MS F Between treatments | 1 6.67 I 2.00 Factor A (ROWS) 18.00 Factor B (COLUMNS)...
Source Between treatments Within treatments Sum of Squares (Ss) df Mean Square (MS) 2 310,050.00 2,650.00 In some ANOVA summary tables you will see, the labels in the first (source) column are Treatment, Error, and Total Which of the following reasons best explains why the within-treatments sum of squares is sometimes referred to as the "error sum of squares"? O Differences among members of the sample who received the same treatment occur when the researcher O Differences among members of...
Question Completion Status QUESTION 4 Anova: Single Factor SUMMARY Groups Count Sum Average Variance A 4 108 27 32.66666667 B 4 96 24 13.33333333 4 120 30 56 ANOVA Source of Variation SS df F crit MS P-value F Treatments 72 36 1.058823529 0.386396621 4.256494729 Error 306 9 34 Total 378 11 Based on the Results above of Single Factor ANOVA: the MSTR O 36 O 378 O 72 O 34 Click Save and Submit to save and submit. Chick...
An experiment has a sinale factor with 3 aroups and 5 values in each aroup. In determining the among-group variation, there are 2 degrees of freedom. In determining the within-group variation, there are12 degrees of freedom In determining the total variation, there are14degrees of freedom. Also, note that SSA = 42 SsW 84, SST= 126, MSA = 21, MSW = 7, and FSTAT = 3. Complete parts (a) through (d). a. Construct the ANOVA summary table and fill in all...
The calculations for a factorial experiment involving four levels of factor A, three levels of factor B, and three replications resulted the following data: SST 291, SSA 26, SSB 25, SSAB 180. =.05, Show entries to 2 decimals, If necessary Set up the ANOVA table and test for significance using the answer is zero enter "0". Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value X X Factor A Factor B Interaction 24 Error 35 Total...
Problem 4: Complete the ANOVA table based on the following data: Replications Standard Deviation Factor A Level 1 Level 2 Mean 15 ANOVA Table Degree Freedom of Sum of square Mean sum of F-valuc Source error square error Treatment Error Total NA NA NA Recall that for single-factor ANOVA, we have the following -SSTreatments+SSp where ss,-Σ Σ(y)-T)-total sum of squares n Σ(vi-r-treatment sum of squares i- SSE _ Σ Σ(w-5)2-error sum of squares Given a dataset like the following: Treatment...
Most questions answered within 3 hours.
-
Little’s Law: Val d’Costa is a world famous ski village in the
French Alps. Because of...
asked 1 minute ago -
Find the absolute error D for the calculation if A + B/C=D A=
9.4 +/- 0.4...
asked 14 minutes ago -
New Air Heating and Cooling, manufactures furnaces and central
air units. The company pride itself on...
asked 28 minutes ago -
A coach uses a new technique to train gymnasts. Seven
gymnasts were randomly selected and their...
asked 2 hours ago -
While rotating the tires on your car you notice a rock [mass =
0.1 Kg] stuck...
asked 4 hours ago -
Using MARS simulator, write MIPS programs according to
the following scenarios: Receive a positive integer number...
asked 6 hours ago -
An object in front of a concave mirror has a real image that is
11.5 cm...
asked 6 hours ago -
Consider the reaction, C3 H8 + O2 --> CO2 + H2O. How many
moles of O2...
asked 8 hours ago -
You and your opponent both roll a fair die. If you both roll the
same number,...
asked 8 hours ago -
In a study of the accuracy of fast food drive-through orders,
Restaurant A had 257 accurate...
asked 8 hours ago -
Identify and describe in detail the four categories of
institutions that could be included in a...
asked 8 hours ago -
In python
class Customer:
def __init__(self, customer_id, last_name, first_name, phone_number, address):
self._customer_id = int(customer_id)
self._last_name =...
asked 8 hours ago