Question

2. (20 points) Write a method that accepts a temperature in Fahrheit as a parameter and returns that same temperature in Celsius. For example, if your method were called with the parameter 212, it would not print anything but would return 100. Name CSCI 161-(01.02.03)-Homework 02-Page 2 3. (20 points) Write a main method that prints a table of the Celsius equivalents of every 5tlh Fahrenheit temperature between 20 and 90. Assume that this is in the same class as the previous problem. Output should look something like this: 20 25 30 35 40 45 50 -6.666666666666667 -3.888888888888889 1.6666666666666667 4.444444444444445 7.222222222222222 10.0 60 65 70 75 80 85 90 15.555555555555555 18.333333333333332 23.88888888888889 26.666666666666668 29.444444444444443 32.22222222222222

Need the answer in Java, thank you!

Answer 1

Program 2:

import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner in = new Scanner(System.in);
System.out.println("Enter the temperature in Fahrenheit: ");
double fahrenheit = in.nextDouble();
double celsius = (fahrenheit-32)*(0.5556);
System.out.println("Temperature in Celsius: "+celsius);
}
}

Program 3:

import java.util.*;
public class MyClass {
public static void main(String args[]) {
Scanner in = new Scanner(System.in);
System.out.println("F\tC");
for(int i = 20; i <= 90; i = i + 5){
double fahrenheit = i;
double celsius = (fahrenheit-32)*(0.5556);
System.out.println(fahrenheit + "\t" +celsius);
}
}
}

Let me know if you have any queries or clarifications.... :)