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a. (2) On Graph 1, extrapolate and give the freezing point of the pure solvent to the nearest 0.1°C. Show the extrapolation o
2 .5 2 1.5 1 0.5 Temperature (deg C) 0 -0.5 -1 -1.5 -2 -2.5 0 2 5 6 3 Time (min) Graph 1. Freezing point of pure solvent Temp
a) In graph 1, see the freezing point is 0.5 °C. b) In graph 2, see the freezing point is - 6.5 °C c) The freezing point chan
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Answer #1

Yes this answer is correct as Freezing point of solvent = 0.5°C by Freezing point of solution 2 -6.50 Freezing point point of

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