In an acid-base titration, 33.12mL of 0.1177 M H2C2O4 was titrated with 0.2146 M NaOH to...
In an acid-base titration, 33.12mL of 0.1177 M H2C2O4 was titrated with 0.2146 M NaOH to the end point. What volume of NaOH solution was used? NaOH(aq)+H2C2O4(aq) ---> Na2C2O4(aq) + H2O(l)
Homework Answers
This question is based on the molarity, volume and moles concept. We evaluate the moles of H2C2O4 and then find the volume of NaOH.
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In an acid-base titration, 33.12mL of 0.1177 M H2C2O4 was
titrated with 0.2146 M NaOH to...
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Please show steps and please explain why the answer is what it
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24B) The 40mL 0.2 M formic acid is titrated with a 6.0mL of
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Strong acid-titrated with strong base. Suppose the titration was reversed in question 2. If you titrated...
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An unknown acid is titrated with a strong base (NaOH) to produce the above titration curve....
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the above titration curve. Key points on this graph reveal
important information about the substance and the solution created
with it.
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24A) 40mL of 0.2 M formic acid is titrated with a strong base
(NaOH= 0.5 M). Determine the pH before any base has been added.
Please show steps and please explain why the answer is what it
is.
24B) The 40mL 0.2 M formic acid is titrated with a 6.0mL of
strong base. Here NaOH can be treated as a conjugate base and
formic acid is the acid.
please show steps and explain!
Us (24-25, Acid/base, aqueous equilibrium) 24A) (4...
Weak Acid-Strong Base Titration Date Nanse PRE-LAB OUESTIONS 1 Calculate the molarity of a NaOH solution that was used to titrate 1.2 g of potassium acid phthalate if 37.50 ml of the base were reauired to get to the end point of the titration. 2 It takes 12.45 ml. of a 0.500 M NaOH solution larity of the acid to titrate 30.0 mL of acetic acid. What is the mo- 3. Using the titration curve below, calculate the K, of...
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What volume of NaOH is needed to reach the equivalence point
(the point where you added equal moles of NaOH to the
acid)? Select one of the following : ["10 mL", "5
mL", "20 mL", "30 mL", "40 mL", "25 mL", "15 mL", "35 mL"]
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