Question

21.5 KN Determine the total moment about point of the forces The and TCH - 13.0 kN acting on structure shown in Fig. I. (BK = 1.5 m; CL = 1.0 m: OG 2.5 in: GF 0.5 m. FE = 0 5 m, GH - 2.0 m).

Answer 1

ANSWER

Given data

TBE = 21.5KN

TCH = 13.0KN

BK = 1.5m

CL = 1.0m

OG = 2.5m

GF = 0.5m

FE = 0.5m

GH = 2.0m
from the given diagram Coordinates are 0(0,0,0) B(0,81-15) € (3,00-0.5) c ( 11610) H (9.510,a). 7 BE = 21.5 Bê a 315 (3-0, 6-8, 05-61.5)) V 32+82 + 6084 (19) Be = 215 3,-8, 4 19+64th Be = 2165 3, -81 +) 1 74 Bè : 215(en The State de = 7.4989 – 19.9949 +2.499 kw. Tch = 130 À =12 (9.5-1,0-6,2-0) 8.5-1) 4 6²+22 h = 13 1.5 1:5, -6, V 1.52+62+28

c = 13 15, -6,9 - ✓ 2-25+36 +4 A = 13 (1.5 , 26, 2) V 42.25 cha gl 12 + 4E KN Total moment about point lo' - Mo .. = PBXT BE +8 x 7cH 908-15 [7.498 -19.994 2.499 + 1 6 0 1 3 -12 4 Mo - (-9.9999 1-2949 -59.984 6J+647-4_308) - (14-0019–15:2449 _8998 A) kw-m. - Fillo = 1/6)= V84-001) 24 445.287) + (-89.90) V 19602800+239.47100 9+8096.4004 = V8524-899 - 92.330 KN-my