Question

Find an equation of the parabola whose graph is shown. Square has area 9

Answer 1

Solution

In the given diagram there is a square which has area 9 i.e. if we let a side of square is then

$a^2=9$

$a=\sqrt{9}$

$a=3$

Now we can see that the vertex of parabola is at origin and directrix passes through the point (dictance of directrix is 3 unit from origin in the left side) and parellel to y-axis then equation of directrix is

(-3.0)

x= -3 or I +3=0

Now by standard formula as given in following diagram

Focus of given parabola will be at

Now the equation of parabola-

$y^2=4ax$

(3) 4 = دو

$y^2=12x$