Question

A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r Overscript right-arrow EndScripts = (2.00 m) i Overscript ̂ EndScripts - (3.00 m) j Overscript ̂ EndScripts + (2.00 m) k Overscript ̂ EndScripts, the force is Upper F Overscript right-arrow EndScripts = Fx i Overscript ̂ EndScripts + (7.00 N) j Overscript ̂ EndScripts - (6.00 N) k Overscript ̂ EndScripts, and the corresponding torque about the origin is tau Overscript right-arrow EndScripts = (4.00 N·m) i Overscript ̂ EndScripts + (12 N·m) j Overscript ̂ EndScripts + (14 N·m) k Overscript ̂ EndScripts. Determine Fx.

Answer 1

+18