Question

Juan invests a total of $30,000 in two accounts. The first account earned a rate of return of 9% (after a year). However, the second account suffered a 5% loss in the same time period. At the end of one year, the total amount of money gained was $-100.00. How much was invested into each account? ş was invested at 9% and $ was invested at 5%.

Answer 1

Let investment at 9% = then investment at 5% =$30000-x) Total amount of money gained one year xx 100 x1 +(30000-X)x(6) x 1 in مج It is given 0.14X-1500 -100.00 0.190 -1500 = -100.00 0.142 = 1400 $10000 and 30000-X = $ 20000 was invested at 9% and & 20000 was invested at 5% Hence & 10000