Question

TOT wOUTO NO. Stick-off Plata (metal 6mm or glass 12 mm thick) Apparatus: Balance Readable to 0.1 kg) compacting bar (1.8 +/- 0.1 kg) Vibrator (Frequency 70000 vibrations / min.) Container Trial No 1 Trial No 2 Trial No. 3 Mix 1 20% GGBS TRUE Sourso of Mix Time of Concrete Production Elapsed Time: Slump Form: a. True b. Shoar c. Collapse Slump Value SP I Slump value + SP Temperature of Frosh Concreto Weight of Dry Empty Container Weight of Containor Filled With Compacted Concreto Net Wolght of Compacted Concreto mm 60 22.5 15.7 24.05 0,35 kg kg C=B.A | Density of Concrete kg/m 2474 V= volume of container Average kg/m Test Method Sampling Mothod Specimen Preparat. Mid. T. Method Variation Remarks BS 1881 : Part 102 & 107 : 1983 BS 1881 : Part 101 (sampling of fresh concrete) BS 1881: PART 2: 1983, clauso 5 V = (0.15x0 15x0.15) m Tosted By Checked By frnd-the following. 1 2 3 Slump value, (before & after using Admixture, it was used) Temperature of Fresh Concrete (If measured) Density of Fresh Concrete (if measured & calculated)

Answer 1

The given image is the test result of slump cone test made on 20% GGBS concrete.

To answer the questions, it is evident from the test result that

1) Slump Value (before and after using admixture) = 60 mm.

Here, Superplasticizer (SP) has been used as an admixture. In this case, the addition of superplasticizer does not affect the slump value of concrete.

2) The temperature of fresh concrete = 22.5° C (It is measured and provided in the data).

3) Density of fresh concrete = 2474 kg/m3

Calculation

Weight of container = 15.7 kg

weight of container after filling concrete = 24.05 kg

Net weight of concrete = 24.03 -15.7 = 8.35 kg

Volume of container = 0.15 x 0.15 x 0.15 = 3.375 x 10-3 m3 (Given)

Density of concrete ,

$density = \frac{weight}{volume}=\frac{8.35}{3.375\times 10^{-3}}= 2474.07 kg/m^{3}$

Hope everything is clear and the explanation is enough. Thank you.