Question

A chemist in a laboratory drops a 1 liter bottle of acetone and the bottle immediately breaks and all the acetone evaporates. The ventilation in the lab is turned off because of the warm spell. The laboratory measures 30 feet X 25 feet X 10 feet.

Acetone has the following properties: Molecular weight 58, Density of the liquid 0.792 grams per milli-liter, TLV( Threshold Limit Value) 750 PPM, Lower explosive limit 2.6%.

Questions: 1.) What is the concentration of acetone vapors in the room? 2.) Has the TLV been exceeded? 3.) Has the concentration reached the lower explosive limit?

Answer 1

W WE 2. classmate Date Page Solution Given. Volume od enclosure (V2 = 30f7 x 26 ffxvogi molecular weight otacetonecm) 3.58 15m / 16-mol det cbe concentration of acetone vapowus in room TLV_value ? Iso ppm Panetone = 0.tel gm me Ventilation is tuned opp- became of Waum peu. ?? Qu 20. Wewekac Qm - RQUE Nowe Vode tmature vehere Cami is the evolution rate of volarle materiah and & Guaj ventilation rate ( wolf time) S & is mon - ideal mining_factor =) Vdc = am - C -> Vol 2 Qm dt now, we know Qm - MKA psal 1 Rg TL for acetone, Ko 0.83 cms 18)Y3 as Kako (.)3 is 0.68 cmolis 0.022309 $1$ peat - 231 mm Hg - 0.3039 am A = $ 130 x 20) 4+2 S . Rg = 0.7302 ft arm / 1b molºr = 210 c = 536 "R am - (0.02231 bt ). ( 150 ft x 6.3039 alin. To 1302 Baum 1930:R) 0.4302 H3 am en molR = Sammet with CamScanner 0.73 lbm see

classmate Date page V = 7:00 ft3 ovsdo - Qmfat 3) V.G - Am.t Mass of acelone_ = 10°me x 0.492gm me 7929m. 792 gm of acetone euaporates 2 Time required = 7929m 0.73 lbm, u $3.592 9m sec (om - =_3:318 seconde | 2) 7500 ft3 a concentration = 0.453x453.59290 * 2.318 Dec sec 2) C = 0.1055 gm L1t3. Lower explosive limil - 2.6.). 20.026 gay ft 3 2 LEL has not been exceeded. - (2) V . Cppm = mungu x 106 where moongo represent tett mat denilly & Vb represent bulk volume. 0-142gmt.mnt 4106 1792 gm You f73 10-3 m3 100 ft3 0.02831 m3 29.409 ppm and TV EU ppm R okante Vivithalue has not been exceeded. canner