Homework Answers
ln (K2/K1) = dH/R (1/T1 - 1/T2)
K1 = 2.1 x 103 ,T1 = 298 K
K2 = ? , T2 = 605 K
dH = -23500 J/mol , R = 8.314 J/mol.K
ln (K2/2100) =(-23500 J/mol) /(8.314 J/mol.K) (1/298 - 1/605)1/K
ln K2 - 7.65 = -2826.56 (0.00170)
ln K2 = 2.8369
K2 = 17.06
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