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Question 6 Your answer is partially correct. Try again. In the figure a 19 V battery is connected across capacitors of capacitances C1 = C6 = 5.0 pF and C3 = C5 = 2.5C2 = 2.5C4 = 5.5 UF. What are (a) the equivalent capacitance Cea of the capacitors and (b) the charge stored by Ceg? What are (c) V1 and (d) 41 of capacitor 1, (e) V2 and (f) 42 of capacitor 2, and (9) V3 and (h) 93 of capacitor 3? HH (a) Number 16.6 (b) Number 96 (c) Number 11 (d) Number (e) Number

Answer 1

son. * Volg C = G = 5NF, C₂=(5=2.5 (2 = 2.54 asis 2 C₂ = 5.5 . = 2.2 MA 25 Cy= s.s = 2.2 ME a) for Carl = section of CS*(; + C2 - he 5+63 (3:5) + 2.2 Tot = 2.75 +2.20 -24.95 ME for section ? 2 Cerr = C, flg =) 10 ME / both are in parallery Cy is in parallel with section- (Cel cery & Cu =) 2-2f4.95 -) 7.15 Mf Cer of arcuit (Cer") & Cera [ Ikast Kegil & Cazz e) 7.15 x 10 . 11 7015+10 .4-12 ur . Cer of circult = 4.17 MI b) Qu Cee xv -> 4.14x19 N = 79-23 Mei

c qn across changes we have some serres each s Connection we have Connection Ceysa choro - 7.923 v 0 = Ceza x ve vie) 79.29 10 voltage across Cepz Since 1. Cez is coorallel 7.923 v combination of co and Ca E292) Bors d) :: Pes se Na -> 5*7.923 = 582 to 39.61 MC e) since Cee's is parallel combination of Cy, (C5, (3), and G .: Viced's -> 19 - Veeqa =) 19-7-923 ) 11.07v C2 = 11.0tr C2 X V2 2-2x11.07 ) 24.35 MC - g) for Cz and Cs Ara 11.07~ Since (3=65 19 = (Syly1107 -> 5.5 x1102 c3f(s/ 30.44 MG) They are in series R=G x V D P 3014 1 2) 17 Yeg a Ves = Ar = 11.87 - 5. 535v 67 93 = C₂ x Vez

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