Question

View Policies Current Attempt in Progress Determine the forces in members BI, CI, and Hl for the loaded truss. All angles are 30°, 60°, or 90° на NI 2.2 KN 4.3 KN Part 1
Plz use joint method to solve the problem

Answer 1

Dues) FBD am I a H a G 0% 1 Au 22 KN 4.3KN 4.3 KN z Mp=0 4.3 (A+) +2.2x (2a+2) – 34. Ay =o 2.2X 4:3x3a + 50x2,2 = 34. Ay [Ay = 3.98 KN

Joint A: 460 FAT {fy=0 Ay - FAO sin 60=0 faB = _ 3.98 sin 60 FAB = 4.6 KN (C) I fx=0 far - FAB COS60 = 0 . far = 2.3 KN (T) Joint B: O foc Along y' direction : for a FAB sin 30 x 30 7600 for for-4.6 singo f8p = 2.3kN] (T) 1. FAB

Joint 1: For FATA 4 60 60 FHI 2.2 KN Along y-directions Efy = 0 - fcq señ60' – for sin 60+2.2=0 - FCI sin 60° ~ 2.3 sin60 +2.250 for = 0.24 03 KNICT) {fx=0 Fra + for COS 60 – fer cos 60^-FAT =0 FH1 +0.2403 COS 60°– 2.3 cos GO – 2:3 = fag = 3.33 KN) (7)