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A Radar transmits a 6µSec pulse observed two targets at the same azimuth and elevation. One...

A Radar transmits a 6µSec pulse observed two targets at the same azimuth and elevation. One target is 610 m behind the other. Since this distance is less than the range resolution, only one pulse will be received. How long will this pulse live? (c=3x108)

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Answer #1

Since the distance between the two pulse is 610m, the pulse will be short lived

Now the distance d =610m

c=3x108

t=

610 3 108

t=2mu s

Thus, the pulse will be t=2mu s long.

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