Question

Both parts please

Problem 22.34 A cube has sides of length L 30.310 m. It is placed with one corner at the origin as shown in the figure (Figure 1). The electric field is not uniform but is given by E (-4.31 N/(C. m) )zi (2.71 N/OC.m) )zk. Figure 1 of 1 S2 (top) (back) Se S3 (right side) (left side) S4 (bottom) S5 (front) Part A Find the electric flux through each of the six cube faces S1,S2,S3,S4,S5, and S6 Enter your answers in ascending order separated by commas. (N/C) m2 Submit My Answers Give Up incorrect: Try Again; 5 attempts remaining Part B Find the total electric charge inside the cube. Submit My Answers Give Up Incorrect; Try Again, 5 attempts remaining Provide Feedback Continue

Answer 1

electric flux is given by

flux = E.A

flux = E*A*cos(theta)

theta angle between E and A.

E = - 4.31 i + 2.71 k

surface area of S1 = 0.31^2 (-i)

flux through S1 = - 4.31*(- 0.31^2) = .414 N.m/C

surface area of S2 = 0.31^2 k

flux through S2 = 2.71* 0.31^2 = 0.26 N.m/C

surface area of S3 = 0.31^2 j

flux through S3 = 0* 0.31^2 = 0 N.m/C

surface area of S4 = 0.31^2 (-k)

flux through S4 = - 2.71* 0.31^2 = - 0.26 N.m/C

surface area of S5 = 0.31^2 i

flux through S5 = - 4.31* 0.31^2 = - 0.414 N.m/C

surface area of S6 = 0.31^2 (-j)

flux through S6 = 0*0.31^2 = 0 N.m/C

B)

total electric flux = Q/eo

total electric flux = 0.414 + 0.26 + 0 - 0.414 - 0.26 + 0 = 0

Q = 0