here,
the radius of pulley , r = 2 m
m1 = 8 kg
m2 = 5 kg
s = 5 m
the acceleration of system , a = net force /effective mass
a = ( m1 - m2) * g /(m1 + m2)
a = ( 8 - 5) * 9.81 /(8 + 5) m/s^2
a = 2.26 m/s^2
a)
the speed of first mass , v1 = sqrt(2*a * s)
v1 = sqrt(2 * 2.26 * 5) m/s = 4.76 m/s
b)
the speed of blocks is same
the speed of mass 2 is 4.76 m/s
c)
the angular velocity of the pulley , w = v/r
w = 4.76 /2 rad/s = 2.38 rad/s
d)
the angle covered , theta = s /r
theta = 5 /2 rad = 2.5 rad= 143.3 degree
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