Question

In order to defeat Bowser, suppose Mario launched a stone from his sling with an initial velocity of 30.5 m/s at an angle θ=20 degrees above the horizontal. The stone flies through the air and strikes Bowser between the eyes exactly 2.00 seconds after it was released. Assume Mario and Bowser are standing on flat ground, and the stone strikes Bowser on its way back down (after reaching its maximum height). You may neglect air resistance.

A) how far away is Bowser standing from Mario?

B) How many seconds after Mario released the stone did it reach its maximum height?

C) Suppose Mario released the stone from about his eye-level, and the stone eventually strikes Bowser at his eye-level (between the eyes). How many feet taller is Bowser than Mario (use 1 m = 3.28ft.

D) What is the stone's total velocity (magnitude and direction) just before it strikes Bowser between the eyes?

Answer 1

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