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Suppose that Upper A 1A1 and Upper A 2A2 form a partition of the sample space...

Suppose that Upper A 1A1 and Upper A 2A2 form a partition of the sample space S with Upper P left parenthesis Upper A 1 right parenthesis equals 0.75PA1=0.75 and Upper P left parenthesis Upper A 2 right parenthesis equals 0.25PA2=0.25. If E is an event that is a subset of S and Upper P left parenthesis Upper E vertical line Upper A 1 right parenthesis equals 0.06PE A1=0.06 and Upper P left parenthesis Upper E vertical line Upper A 2 right parenthesis equals 0.09PE A2=0.09?, find Upper P left parenthesis Upper E right parenthesisP(E). Upper P left parenthesis Upper E right parenthesisP(E)equals=nothing

math   Statistics-And-Probability   
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From the given information, the prior and conditional probabilities are P(4)-0.75. P(4)-0.25. P(E4)-0.06. P(E|4) 0.09 Compute

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