(1 point) Find an orthonormal basis of the plane x1 + 2x2 – x3 = 0....
(1 point) Find an orthonormal basis of the plane X1 + 4x2 – x3 = 0. Answer: To enter a basis into WebWork, place the entries of each vector inside of brackets, and enter a list of these vectors, separated by commas. For instance, if your basis is 2 then you would enter [1,2,3], 3 [1,1,1) into the answer blank.
(10 pts) Find an orthonormal basis of the plane 21 - 4.62 - X3 = 0.
; Let at be a linear transformation as follows : T{x1,x2,x3,x4,x5} = {{x1-x3+2x2x5},{x2-x3+2x5},{x1+x2-2x3+x4+2x5},{2x2-2x3+x4+2x5}] a.) find the standard matrix representation A of T b.) find the basis of Col(A) c.) find a basis of Null(A) d.) is T 1-1? Is T onto?
Find an orthonormal basis for the plane viewed as a subspace of R3. Z (-1,0,2) (0,-1,0) (0,1,0)
Given the LPP: Max z=-2x1+x2-x3 St: x1+x2+x3<=6 -x1+2x2<=4 x1,x2<=0 What is the new optimal, if any, when the a) RHS is replaced by [3 4] b) Column a2 is changed from[1 2] to [2 5] c) Column a1 is changed from[1 -1] to [0 -1] d) First constraint is changed to x2-x3<=6 ? e) New activity x6>=0 having c6=1 and a6=[-1 2] is introduced ?
Solving Systems of Linear Equations Using Linear Transformations In problems 1-5 find a basis for the solution set of the homogeneous linear systems. 2. X1 + x2 + x3 = 0 X1 – X2 – X3 = 0 3. x1 + 3x2 + x3 + x4 = 0 2xı – 2x2 + x3 + 2x4 = 0 x1 – 5x2 + x4 = 0 X1 + 2x2 – 2x3 + x4 = 0 X1 – 2x2 + 2x3 + x4...
Find an orthonormal basis of the plane in R3 defined by the equation 2a yz0
Consider the following LP problem max z = x1 +2x2 + x3 + x4 s.t. x1 + 2x2 + x3 く2 +2x3 く! X1, x2, x3, x4 20 a) Obtain the dual formulation of the LP.
Solve this problem using the two-phase method. What special case do you observe? Max Zz4X1-2X2+X3 X1+2X2+X3 3 2X1-3X2+6X3 100 X1,X2,X3>0
5) (20 points) a) Show that the vectors x1 = (1, 1, 0)T , x2 = (1, 0, 1)T , x3 = (1, 0, 0)T are linearly independent. Do they form a basis of R3 ? Explain. b) Find an orthonormal basis of R3 using x1 = (1, 1, 0)T , x2 = (1, 0, 1)T and x3 = (1, 0, 0)T .