Question

The member is supported by a pin at A and cable BC. Suppose that T = 2.5 m and the cylinder has a mass of 35 kg. (Figure 1) Determine the tension in the cable BC Express your answer to three significant figures and include the appropriate units. O! A Thc = 1057 mo ? kN Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining Figure 10f1 Part B Determine the components of reaction force at the support A using scalar notation. Express your answers using three significant figures separated by a commas. O AXO IT vec Az. Ay. Az = 0.858,0.515,0 Submit Previous Answers Request Answer * Incorrect; Try Again; 5 attempts remaining

Answer 1

solution free body diagram m=35kg VAyg Ax Co-Ordinates A(244,7) = (0,0,0) B(24/2) = (0,05, 1) Way c(X,Y,Z) = (2.5, 1,0) D (249, 2) - (2.5,-1,0) 34 3.35 N Weight (W2 = mg = 35*9.89 Weight vector Was-W = -343.35 Â Vector of CB (NEB) = 2B-re = 6-2.531+(1+015); +(0-D & TEB = (-2.59 + 1.59 th hm

Tention to a Tolent) +0.3256 Mi8 10:48 Tapet Foruî-0-4829 + 0.315 i'] te veroor Ac, (rac) Te- rpe = (2,5 49 ) m vertor AD (NAD) =%TA sp : -sº-3 ) ), Reaction at A C RA = Axit Ay it Azj moments at a MA = (MA)zi +(MA)ek For equilibrium taking moment about point A - EMA TO MA +(NAC XTF (B) + (NADOW) EO [(ma) ni + (ma)*] + (2.5i +3x[-0.sui cookie +(2.5i-j)x(-343.5K) =0 ? (2.5i +j ) x Ter [-0-801 -0.4873 +0.32567 ma - 0.8171 -0.4873. Tree +0.325kn a 1-0,811 -0.487 01325 | Tere | 2.5. 1 0

= (-12125 Terk - 0.8125 Ter i + 0.811 TeBK) (2.51-;) x (-34305 *) = 12.5 - 10 loo - 343.5 L 343,5 - (343.5i +8581453 ) : [[mak i +(Ma)x) + k - 0.8125 Tegi to +(343.5i +858.45;) -0 [ima), + 0.315 Tek + 343.5]; +5 [0.8125 Teg +858.25 + [lema)ą +.4065 Tc]* 20 comparing "j' terms -0.8125 TCB + 858:75 =0 I TEB : 858.75 0,8125 i Tension in cable CB TCB = 1056.9231N EF =D fus + W + RA = 0 (Ax'); +(Ay) aj + Azi + 0.325 TURK -0,487 TCB) – 0,811 Teri - 343.35k co Comparing i terms Ax-Q.811 (105699231) so

lax = 857-165 wl comparing 'j' torms Ay -0.487(1056-9231) so Aya 514.722N comparing k forms Az +0.325(1056.9231) - 343.35 =0