Consider the titration of 100.0 mL of 0.100 M methylamine (CH3NH2) with 0.500 M HNO3. Calculate the pH at the following volumes of acid added.
For CH3NH3+, pKa = 10.632
(a) Find the equivalence point volume.
(b) 0 mL
(c) 9.0 mL
(d) 10.0 mL
(e) 20.0 mL
(f) 30.0 mL
Consider the titration of 100.0 mL of 0.100 M methylamine (CH3NH2) with 0.500 M HNO3. Calculate...
Consider the titration of 100.0 mL of 0.200 M CH3NH2 by 0.100 M HCl. For each volume of HCl added, decide which of the components is a major species after the HCl has reacted completely. Kb for CH3NH2 = 4.4 x 10-4. 0.00 mL HCl added 50.00 mL HCl added 200.00 ml HCl added 300.00 mL HCl added yes no H+ yes no H2O yes no Cl- yes no CH3NH2 yes no CH3NH3+ Tries 0/45 yes no H+ yes no H2O yes no Cl- yes no CH3NH2 yes no CH3NH3+...
Consider the titration of 100.0 mL of 0.100 M /hydrazine () by 0.200 M . Assume that hydrazine is monoprotic. Determine the following: a. pH before any HNO3 is added b. volume of acid to reach the equivalence point c. pH when 20.0 mL of HNO3 has been added d. pH when 25.0 mL of HNO3 has been added e. pH when 40.0 mL of HNO3 has been added f. pH when 50.0 mL of HNO3 has been added g....
Consider the titration of 100.0 ml of 0.200 M CH3NH2 by 0.100 M HCl. (Kb for CH3NH2 = 4.4 x 10^-4) At what volume of HCl added, does the pH = 10.64?
Consider the titration of 100.0 mL of 0.200 M CH3NH2 by 0.100 M HCI (K for CHNH2 4.4 x 10) At what volume of HCl added, does the pH 10.64? XmL
Consider the titration of 40.0 mL of 0.200 M HCIO4 by 0.100 M KOH. Calculate the pH of the resulting solution after the following volumes of KOH have been added. a. 0.0 mL pH = b. 10.0 mL pH = c. 60.0 mL pH = d. 80.0 mL pH = e. 110.0 mL pH = Consider the titration of 100.0 mL of 0.200 M acetic acid (Ka = 1.8 x 10-5) by 0.100 M KOH. Calculate the pH of the...
• example: Titration of 100.0 mL of 0.05 M NH3 with 0.10 M HCI • Calculate equivalence point volume • Calculate pH at the following volumes of acid added • 10.0 mL • 25.0 mL • 50.0 mL • 60.0 mL • Check your answers against the titration curve
Consider the titration of a 25.0 −mL sample of 0.180 M CH3NH2 with 0.150 M HBr. Determine each of the following: a) the initial pH b) the volume of added acid required to reach the equivalence point c) the pH at 4.0 mL of added acid d) the pH at one-half of the equivalence point e) the pH at the equivalence point f) the pH after adding 4.0 mLof acid beyond the equivalence point
Questions 1: Consider the titration of a 24.0-mL sample of 0.175 M CH3NH2 with 0.155 M HBr. (The value of Kb for CH3NH2 is 4.4×10−4 A) Determine the initial pH B) Determine the volume of added acid required to reach the equivalence point C) Determine the pH at 4.0 mL of added acid D) Determine the pH at one-half of the equivalence point. E) Determine the pH at the equivalence point. F) Determine the pH after adding 5.0 mL of...
A chemist titrates 130.0 mL of a 0.0647 M methylamine (CH3NH2 solution with 0.5334 M HNO3 solution at 25 °C. Calculate the pH at equivalence. The p K, of methylamine is 3.36 Round your answer to 2 decimal places Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HNO3 solution added pH =
Consider the titration of a 28.0 −mL sample of 0.170 M CH3NH2 with 0.145 M HBr. Determine each of the following. a) the initial ph b)the volume of added acid required to reach the equivalence point c)the pH at 4.0 mL of added acid d)the pH at one-half of the equivalence point e)the pH at the equivalence point f)the pH after adding 6.0 mL of acid beyond the equivalence point