Question

When the rate of disappearance of O2 is 0.13 Ms−1, the rate of appearance of CO2 is ________ Ms−1.

Answer 1

THE REACTION IS NOT PROVIDED.

SO, I am using this reaction,

C₂H₄ (g)+3O₂(g)→2CO₂(g)+2H₂O(g) [BALANCED]

Rate = change in Concentration/change in time

For a General reation,

aA + bB $\rightarrow$ cC + dD

Rate = -(1/a)*($\Delta$[A]/$\Delta$t) = -(1/b)*($\Delta$[B]/$\Delta$t ) = (1/c)*($\Delta$[C]/$\Delta$t) = (1/d)*($\Delta$[D]/$\Delta$t)

Negative sign is just to show that they are disappearing

So, For our reaction,

C₂H₄ (g)+3O₂(g)→2CO₂(g)+2H₂O(g)

Rate = -($\Delta$[C₂H₄]/$\Delta$t) = -(1/3)*($\Delta$[O₂]/$\Delta$t ) = (1/2)*($\Delta$[CO₂]/$\Delta$t) = (1/2)*($\Delta$[H₂O]/$\Delta$t) ---------------A

ANSWER -

Given

rate of disappearance of O₂ = 0.13 M/s

Rate of appearance of CO₂ = ?

From A,

-(1/3)*($\Delta$[O₂]/$\Delta$t ) = (1/2)*($\Delta$[CO₂]/$\Delta$t)

rate of appearance of CO₂ ($\Delta$[CO₂]/$\Delta$t)= (2/3) * rate of disappearance of O₂ ($\Delta$[O₂]/$\Delta$t)

Put the values,

rate of appearance of CO₂ = (2/3) * rate of disappearance of O₂

rate of appearance of CO₂ = (2/3) * 0.13 M/s

rate of appearance of CO₂ = 0.0867 M/s [ANSWER]