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The power dissipated in an electrical circuit is the current times the voltage drop. In this case, I times the emf across them/s speed of wire = 1 l l show force Time (s) 2.00 + + + + + + + + + + + + + + + + + ++ ++ + + + + + + + + + + + + + + + + +

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Answer #1

Criven emf of battery v= -14.278 v. - current is 5-5.A (from graph) K.) power dissipated p= iv=ts) 1-4:278) - Witwatt 1 =7113

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