Question

15. -12 points SerPSE10 37 6 P029 The critical angle for total internal reflection for cubic zirconia surrounded by benzene is 43.0°Calculate the polarizing angle for cubic zirconia. Need Help? Read It Submit Answer Practice Another Version 16. 2/2 points Previous Answers SerPSE10 37.00.007 If plane polarized light is sent through two polarizers, the first at 45° to the original plane of polarization and the second at 90° to the original pla passes through the last polarizer?

Answer 1

Polarizing angle is also known as Brewster's angle, which is given by:

tan $\theta_p$ = n_z/n_b

Now given that critical angle for cubic zirconia surrounded by benzene is 43.0 deg, So

critical angle = $\theta_c$ = arcsin (n_b/n_z)

n_b/n_z = sin $\theta_c$

n_b/n_z = sin 43.0 deg = 0.682

So

$\theta_p$ = arctan (1/0.682)

$\theta_p$ = 55.7 deg

OR use standard value of 'n' for zirconia and benzene

n_z = refractive index of cubic zirconia = 2.20

n_b = refractive index of Benzene = 1.501

So,

$\theta_p$ = arctan (2.20/1.501)

$\theta_p$ = 55.7 deg

Let me know if you've any query.