Question

Set up and evaluate the definite integral for the area of the surface generated by revolving...

Set up and evaluate the definite integral for the area of the surface generated by revolving the curve about the y-axis. (Round your answer to three decimal places.)

y = 1 − (x^2)/36 , 0 ≤ x ≤ 6

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Answer #1

* Y- |x? 36 ; of x26 ya 18 2 A 2T dx و a 6 27x THAdx I x x² + 324 dx 0 Substitute U= x² + 324 adna £du 18 [sens min 3 sub du

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