Question

1) An object is 31.9 cm from a spherical mirror, along the mirror's central axis. The mirror produces an inverted image with a lateral magnification of absolute value 0.763. What is the focal length of the mirror? 2) More lenses. Object O stands on the central axis of a thin symmetric lens. For this situation (see the table below, all distances are in centimeters), find (a) the lens type, converging or diverging, (b) the focal distance f, (c) the image distance i. It also refers to whether (d) the image is real or virtual, (e) inverted or noninxerted from O, and (f) on the same side of the lens as Oor on the opposite side. (a) (b) (d) (e) (6) Type f Pi m R/V I/NI Side (c) +19 +1.29 3) A grasshopper hops to a point on the central axis of a spherical mirror. The absolute magnitude of the mirror's focal length is 49 cm, and the lateral magnification of the image produced by the mirror is +0.24. (a) Is the mirror convex (enter 1) or concave (enter O)? (b) How far from the mirror is the grasshopper?

Answer 1

is inverted m =- distance of object from misun om 10 = 3). 9.um. Iml, lateral magnification = 0.763 Since the image magnification - - where u is the image distance u is the object distance 0.763 بلا Hence, v -0.763 31.9 v=24.34 cm According to mirror equations, ㅗ ㅗ where, f is the focal length L + I f 24.34 31.9 0.0411e 0.0313 = 0.0724 f = 13.8 cm 0.0724 Hence, focal length of given mirror is 13.8 cm (Answer)

I hope you find it useful for question 1.