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a rocket shot at 22m/s at 75 degrees above the horizontal explodes into four equal pieces...

a rocket shot at 22m/s at 75 degrees above the horizontal explodes into four equal pieces at the highest point of its trajectory. One piece moves horizontally at 2m/s, a second one moves vertically upward at 3m/s and a third moves at 1.5 m/s vertically downward. What is the velocity of the fourth piece?

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Answer #1

given - het m= mass of Rocket initial velocita ū= ū= 22.60375 î +22.5in 75 î ū = 5.69 î + 2.1.25 het m = mass of each segment

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