Hi the unknown is 2,5-dimethyl-2,4-hexadiene
Given M.F: C8H14
IHD = [(2 x 8) + 2 - 14] / 2 = 2, means either 2 double bonds, 2 rings, or combination
HNMR shows 2 signals, 1 from alkene region & 1 from aliphatic region
CNMR shows 2 signals from alkene region & 2 signals from aliphatic region.
IR:
3024 cm-1, medium, sp2 C-H stretch
2967 to 2857 cm-1, strong, due to sp3 C-H stretch
1621 & 1650 cm-1, medium, due to sp2 C=C stretch
1388 & 1466 cm-1, strong, due to sp3 C-H bending
841 cm-1, strong, due to sp2 =C-H bending
Hope this helped you!
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